Answer:
The coordinates of the image B' is;
[tex](-4,6)[/tex]
Explanation:
Given the figure in the attached image.
The coordinate of the Preimage B is;
[tex]B(6,4)[/tex]
Then rotating it 90 degrees in the counter-clockwise direction;
[tex](x,y)\rightarrow(-y,x)[/tex]
Applying the transformation to the given coordinate, we have;
[tex]B(6,4)\rightarrow B^{\prime}(-4,6)[/tex]
Therefore, the coordinates of the image B' is;
[tex](-4,6)[/tex]
