SOLUTION:
Let Senior citizen ticket be denoted by "s" and child ticket be denoted by "c".
From the statement in the question, we have;
[tex]\begin{gathered} 5s\text{ + 8c = 103 }\ldots\ldots\ldots\ldots\ldots\ldots.(1) \\ 5s\text{ + 4c = 79 }\ldots\ldots\ldots\ldots\ldots\ldots.(2) \end{gathered}[/tex]
Equation (1) - Equation (2)
[tex]\begin{gathered} 5s\text{ -5s + 8c-4c = 103 - 79} \\ 4c=24 \\ c\text{ = }\frac{24}{4} \\ \\ c\text{ =6} \end{gathered}[/tex]
Substituting for c in equation (2);
[tex]\begin{gathered} 5s\text{ + 4c = 79} \\ 5s\text{ + 4(6) = 79} \\ 5s\text{ + 24 = 79} \\ 5s\text{ = 79 -24} \\ 5s\text{ = 55} \\ s\text{ = }\frac{55}{5} \\ \\ s\text{ = 11} \end{gathered}[/tex]
CONCLUSION:
One senior citizen ticket costs $11 and one child ticket cost $6.
