Answer: Q = -1335kJ ( exorthemic reaction)
Calculations:
Given the following parameters :
• Mass =75kg = 75*1000 = ,75000g
,
• Temperature final = 32.5 °C
,
• Temperature initial = 37.5°C
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• Specific heat of human body ,(C,) = 3.56J/g
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• We will use the formula Q = m*c*∆T to calculate total heat lost.
,
• Take note that this is an ,exorthermic reaction. ,therefore q <0
1. Calculate ∆T
[tex]\begin{gathered} \Delta T=T_f-T_i \\ \text{ = ( 32.5 -37.5) }\degree C \\ \text{ =-5 }\degree C \end{gathered}[/tex]
• Therefore ∆T = -5°C
2. Calculate Q
[tex]\begin{gathered} Q\text{ = mass}\cdot C\cdot\Delta T\text{ } \\ \text{ }=\text{ 75000g }\cdot\frac{3.56J}{g\text{.}\degree C}\cdot\text{ -5}\degree C \\ \text{ =-1335000J} \\ \text{ =-1335kJ } \end{gathered}[/tex]
• Therefore ; total heat lost from an average human when the body temperature drops from 37 °C to 32.5= -1335kJ
