Answer :
[tex]x\text{ = }\frac{11}{14}[/tex]
Here, we want to solve for x
We start by multiplying through by 8
We have this as;
[tex]\begin{gathered} 8\times\frac{3}{8}(2x-3)\text{ = 8}\times\frac{1}{4}-x\times8 \\ \\ =\text{ 3(2x-3) = 2 - 8x} \\ 6x-9\text{ = 2-8x} \\ 6x+8x\text{ = 2 +9} \\ 14x\text{ = 11} \\ \text{x =}\frac{11}{14} \end{gathered}[/tex]