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Answer :

Apply the given theorem to find the expanded form of the given binomial, in this case n is 4:

[tex]\begin{gathered} =x^4+\frac{4}{1}x^{4-1}y+\frac{4(4-1)}{2}x^{4-2}y^2+\frac{4(4-1)(4-2)}{6}x^{4-3}y^3+y^4 \\ =x^4+4x^3y+6x^2y^2+4xy^3+y^4 \end{gathered}[/tex]

The correct answer is this:

[tex]x^4+4x^3y+6x^2y^2+4xy^3+y^4^{}^{}^{}[/tex]