we have that the sum of the internal angles of a triangle is equal to 180 therefore,
for p
[tex]\begin{gathered} p+80+20=180 \\ p+100=180 \\ p+100-100=180-100 \\ p=80 \end{gathered}[/tex]
for q
[tex]\begin{gathered} 45+55+q=180 \\ 100+q=180 \\ 100+q-100=180-100 \\ q=80 \end{gathered}[/tex]
answer: B. p = q
