Given:
The quadrilateral HIJK is inscribed in circle C.
[tex]m\angle IJK=112^{\circ}[/tex]
As we know that, the opposite angles in a cyclic quadrilateral add up to 180 degrees.
[tex]\begin{gathered} m\angle IJK+m\angle IHK=180^{\circ} \\ 112^{\circ}+m\angle IHK=180^{\circ} \\ m\angle IHK=180^{\circ}-112^{\circ} \\ m\angle IHK=68^{\circ} \end{gathered}[/tex]
Answer:
[tex]m\angle IHK=68^{\circ}[/tex]
