As shown in the image:
There are two right triangles:
the triangle are similar
naming the points for easy calculation
measure of the angle zyw = measure of the angle yxw
And the measure of the angle ywz = measure of the angle xwy
So, the triangle WYZ will be similar to the triangle WXY
So, the corresponding side will be in proportion
[tex]\begin{gathered} \frac{wy}{wx}=\frac{wz}{wy} \\ \frac{a}{16}=\frac{4}{a} \\ a^2=4\cdot16=64 \\ a=\sqrt[]{64}=8 \end{gathered}[/tex]
In the right triangle ywz:
using Pythagorean theorem:
[tex]\begin{gathered} yz^2=yw^2+wz^2 \\ b^2=a^2+4^2=8^2+4^2=64+16=80 \\ b=\sqrt[]{80}=8.94 \end{gathered}[/tex]
