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Answer :

[tex]\frac{3^5}{3^3}=3^{5-3}=3^2_{}=9[/tex]

In order to get 1 as result we need to get the exponent 0, because as you must know, every number at power 0 is equal to 1.

[tex]\frac{3^5}{3^5}=3^{5-5}=3^0=1[/tex]

So the answer is:

[tex]\frac{3^5}{3^{5^{}}}[/tex]

Another solution could be:

[tex]\frac{3^3}{3^3}[/tex]

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