Find the length of the shorter leg in a 30 - 60 - 90 triangle where the hypotenuse is 10 units.

Hello!
First, let's draw this right triangle to understand better the problem:
Analyzing the draw, we can use the Property of Sine:
[tex]\sin (30\degree)=\frac{\text{ opposite}}{\text{ hypotenuse}}[/tex]Remember that sin(30º) = 1/2.
Let's replace the values in the formula and solve it:
[tex]\frac{1}{2}=\frac{\text{ x}}{\text{ 1}0}[/tex]Multiplying across:
[tex]\begin{gathered} (2\cdot x)=(1\cdot10) \\ 2x=10 \\ x=\frac{10}{2} \\ x=5 \end{gathered}[/tex]Right answer: D. 5 units.