The standard circle equation is
[tex](x-x_0)^2+(y-y_0)^2=r^2[/tex]
Where r is the radius of the circle, and O = (x₀, y₀) is the center of the circle.
In our problem, the radius is 32, and the center of the circle is (-3.7, -3.9), then we have
[tex]\begin{gathered} r=32 \\ x_0=-3.7 \\ y_0=-3.9 \end{gathered}[/tex]
Now we just have to put these values on our circle equation
[tex]\begin{gathered} (x-x_0)^2+(y-y_0)^2=r^2 \\ \\ (x-(-3.7))^2+(y-(3.9)_{}_{})^2=32^2 \\ \\ (x+3.7)^2+(y+3.9_{})^2=1024 \end{gathered}[/tex]
The standard form of the equation is
[tex](x+3.7)^2+(y+3.9_{})^2=1024[/tex]
