Answer :
Given:
[tex]x\left(x+2\right)+y(x+2)-5\left(x+2\right)[/tex]Required:
We need to factorize the given expressions.
Explanation:
[tex]x\left(x+2\right)+y(x+2)-5\left(x+2\right)[/tex]The common multiple in all terms is (x+2).
Take out the common term (x+2).
[tex]x\left(x+2\right)+y(x+2)-5\lparen x+2)=(x+2)(x+y-5)[/tex]Final answer:
[tex]\begin{equation*} (x+2)(x+y-5) \end{equation*}[/tex]K)
Given:
[tex]5y^2-10y^3[/tex]
Explanation:
The given expression can be written as follows.
[tex]5y^2-10y^3=5y^2-5\times2\times y^2\times y[/tex][tex]5y^2-10y^3=5y^2-5y^2\times2y[/tex][tex]\text{ The common multiple in all terms is }5y^2.[/tex][tex]\text{ Take out the common term }5y^2.[/tex][tex]5y^2-10y^3=5y^2(1-2y)[/tex]Final answer:
[tex]5y^2(1-2y)[/tex]l)
Given:
[tex]ax+ay+az[/tex]Explanation:
[tex]\text{ The common multiple in all terms is }a.[/tex][tex]\text{ Take out the common term }a.[/tex][tex]ax+ay+az=a(x+y+z)[/tex]Final answer:
[tex]a(x+y+z)[/tex]