Answer :
To answer this question, first, we have to solve 2x-5=15 for x, and then solve every equation for x.
Solving 2x-5=15 for x, we get:
[tex]\begin{gathered} 2x-5=15, \\ 2x=20, \\ x=10. \end{gathered}[/tex]Now, solving for x:
A)
[tex]\begin{gathered} 2x=10, \\ x=5. \end{gathered}[/tex]B)
[tex]\begin{gathered} 2x=20, \\ x=10. \end{gathered}[/tex]C)
[tex]\begin{gathered} 2(x-5)=15, \\ 2x-10=15, \\ 2x=25, \\ x=\frac{25}{2}\text{.} \end{gathered}[/tex]D)
[tex]\begin{gathered} 2x-20=0, \\ 2x=20, \\ x=10. \end{gathered}[/tex]E)
[tex]\begin{gathered} 4x-10=30, \\ 4x=40, \\ x=10. \end{gathered}[/tex]F)
[tex]\begin{gathered} 15=5-2x, \\ 10=-2x, \\ x=-5. \end{gathered}[/tex]Answer: Options B, D, and E.