To solve the system by substitution, first, we substitute the second equation in the first one and get:
[tex]4y+20+y=145.[/tex]
Adding like terms we get:
[tex]5y+20=145.[/tex]
Subtracting 20 from the above equation, we get:
[tex]5y=145-20=125.[/tex]
Dividing by 5, we get:
[tex]y=25.[/tex]
Substituting y=25 in the second equation of the system, we get:
[tex]x=4(25)+20.[/tex]
Simplifying the above result, we get:
[tex]x=100+20=120.[/tex]
Answer:
[tex](120,25)\text{.}[/tex]
