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A single die is rolled twice. The 36equally-likely outcomes are shown to the right.Find the probability of getting two numberswhose sum is 11.First RollSecond RollOD(1,1) (1.2) (1,3) (1,4) (1,5) (1,6)(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)(4.1) (4,2) (4,3) (4,4) (4,5) (4,6)2 (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)B (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Answer :

Explanation

The probability of getting two numbers whose sum is 11 is the ratio of the numbers whose sum is 11 over the total outcome of throwing the dice. This is given as;

[tex]Pr(sum\text{ of 11) =}\frac{2}{36}=\frac{1}{18}[/tex]

Answer

[tex]\frac{1}{18}[/tex]

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