Answer :
[tex]\begin{gathered} \text{Number of of stickers,s = }\frac{48}{f(n\text{umber of friends)}} \\ \text{ } \\ \text{ s = }\frac{48}{f} \\ \text{ by cross mutiplying, we have.} \\ \text{ s }\times\text{ f = }48 \\ \text{ f = }\frac{48}{s} \\ \text{ Therefore,} \\ \text{ when s = 12, f = ?} \\ \text{ f = }\frac{48}{12}\text{ = 4} \\ \text{ when s = 8, f = ?} \\ \text{ f= }\frac{48}{8}\text{ = 6} \\ \text{ when s = 6, f = ? } \\ \text{ f = }\frac{48}{6}\text{ = 8} \\ \text{ } \end{gathered}[/tex]
