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Answer :

The number of innings Barron might have pitched before his latest game, is obtained as follows:

[tex]\begin{gathered} x+6\frac{2}{3}\ge82\frac{1}{3} \\ \Rightarrow x\text{ }\ge82\frac{1}{3}-6\frac{2}{3} \\ \Rightarrow x\text{ }\ge81\frac{4}{3}-6\frac{2}{3} \\ \Rightarrow x\text{ }\ge(81-6)(\frac{4}{3}-\frac{2}{3}) \\ \Rightarrow x\text{ }\ge(75)(\frac{2}{3}) \\ \Rightarrow x\text{ }\ge75\frac{2}{3} \end{gathered}[/tex]

Thus, the number of innings Barron might have pitched before his latest game is:

[tex]\Rightarrow x\text{ }\ge75\frac{2}{3}\text{ innings}[/tex]