Two planes, which are 3950 miles apart. fly toward each other. Their speeds differ by 40 mph. If they pass each other in 5 hours, what is the speedof each?Answer How to enter your answer (opens in new window) 3 PointsKeypad

Given the word problem, we can deduce the following information:
1. The two planes are 3950 miles apart.
2. Their speeds differ by 40 mph.
3. Time =5 hours
To determine the speed of each plane, we first let:
x= speed of the fist plane
x+40 =speed of the second plane
Based on the above information, the combined speed is 2x+40. Our equation would be:
[tex]2x+40=\frac{3950}{5}[/tex]Next, we find the value of x:
[tex]\begin{gathered} 2x+40=\frac{3950}{5} \\ \text{Simplify and rearrange} \\ 2x+40=790 \\ 2x=790-40 \\ 2x=750 \\ x=\frac{750}{2} \\ \text{Calculate} \\ x=375 \end{gathered}[/tex]Hence,
x= speed of the fist plane=375 mph
x+40 =speed of the second plane=375+40= 415 mph