Let us first add 58 to both sides of the equation:
[tex]x^2-6x+58=-58+58[/tex][tex]x^2-6x+58=0[/tex]
And now let us use the quadratic formula to find x
[tex]x=\frac{6\pm\sqrt[]{36-4(1)(58)}}{2}[/tex][tex]x=3\pm14i[/tex]
Hence, the two solutions are
[tex]x=3+14i[/tex]
and
[tex]x=3-14i\text{.}[/tex]
meaning a = 3 and b = 14.
