(-4,-7) and (8,-13)
Slope intercepts equation:
y=mx+b
Where:
m= slope
b= y intercept
Apply the slope formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
Where:
(x1,y1)=(-4,-7)
(x2,y2)=(8,-13)
Replacing:
[tex]m=\frac{-13-(-7)}{8-(-4)}=\frac{-13+7}{8+4}=\frac{-6}{12}=-\frac{1}{2}[/tex]
So far we have:
y=-1/2x+b
Replace x,y by a given point, for example (8,-13) and solve for b
-13= -1/2(8) + b
-13=-4 +b
-13+4=b
b= -9
Final equation:
y= -1/2x -9
