Answer :
The coordinates of the polygon are given, and then dilated by a factor of 1/2.
Hence the new coordinates would be derived as follows;
[tex]\begin{gathered} A(2,4)\rightarrow\times\frac{1}{2} \\ A^{\prime}(1,2) \\ B(-4,-8)\rightarrow\times\frac{1}{2} \\ B^{\prime}(-2,-4) \\ C(0,4)\rightarrow\times\frac{1}{2} \\ C^{\prime}(0,2) \\ D(12,-2)\rightarrow\times\frac{1}{2} \\ D^{\prime}(6,-1) \end{gathered}[/tex]The new coordinates therefore are derived as;
A'(1, 2)
B'(-2, -4)
C'(0, 2)
D'(6, 1)
This is a reduction