Looking at the given arithmetic sequence, we can see that the first term is 2, therefore a1 = 2.
Also, each number is 4 units more than the number before (that is, the common difference of the sequence is 4), so we have the following recursive formula:
[tex]a_n=a_{n-1}+4[/tex]
Now, to find the 8th term, let's use the recursive formula until we reach n = 8:
[tex]\begin{gathered} a_4=a_3+4=10+4=14\\ \\ a_5=a_4+4=14+4=18\\ \\ a_6=a_5+4=18+4=22\\ \\ a_7=a_6+4=22+4=26\\ \\ a_8=a_7+4=26+4=30 \end{gathered}[/tex]
Therefore a8 = 30.
