a) slope-intercept form: y = 2x + 1
b) point slope form: y - 3 = -3(x - 1)
Explanation:
Slope formula:
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex]
a) sidewalk 1 (table 1)
slope = (1-5)/(0-2) = -4/-2
slope = 2
equation of sidewalk 1 in slope-intercept form: y = mx + c
where m = slope, c = intercept
we need to find the intercept using any point: (2, 5) = (x, y)
5 = 2(2) + c
c = 1
slope-intercept form: y = 2x + 1
b) sidewalk 2(table 2)
slope = (-3-3)/(3-1) = -6/2
slope = -3
[tex]poi\text{ nt slope: }y-y_1=m(x-x_1)[/tex]
using any point: (1, 3) = (x, y)
point slope form: y - 3 = -3(x - 1)