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The price of a train ticket consists of an initial fee of $5 plus a fee of $2.75 per stop. Julia has $21 and would like to travel 50 kilometers. She wants to know the largest number of stops she can afford to buy on a ticket.Let S represent the number of stops that Julia buys.What is the largest number of stop that julia can afford?

Answer :

Julia can afford a maximum number of 5 stops

Here, we want to calculate the largest number of stops that Julia can buy with the money she has

The amount of fee for s stops at a rate of $2.75 per stop will be $2.75s

Mathematically, we can model the equation as;

[tex]\begin{gathered} 5\text{ + 2.75s = 21} \\ \\ 2.75s\text{ = 21-5} \\ \\ 2.75s\text{ = 16} \\ \\ s\text{ = }\frac{16}{2.75} \\ \\ s\text{ = 5.82} \end{gathered}[/tex]

Since the number of stops cannot be fractional, it means the largest number of stops to be afforded is 5

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