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Select the atoms whose ions have an electron configuration of nd^6 (n = 3, 4, 5 ...). For example, the 2+ ion for V ends the electron configuration with 3d^3 .Check all that apply.A. Tl B. Fe C. Rh D. La E. Os F. Ti

Answer :

Answer

Correct answers are B. Fe and E. Os

Explanation

For Fe: electron configuration for Fe is

[tex][Ar]3d^64s^2[/tex]

For TI: the electron configuration is

[tex][Xe]4f^{14}5d^{10}6s^26p^1[/tex]

For Rh: Electron configuration of Rhodium is

[tex][Kr]4d^85s^1[/tex]

For La: Electron configuration of Lanthanum is

[tex][Xe]5d^16s^2[/tex]

For Os: Electron configuration is

[tex][Xe]4f^{14}5d^66s^1[/tex]

For Ti: Electron configuration is

[tex][Ar]3d^24s^2[/tex]

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