Answer :
as they are parallel the slope is the same. So we get that the equation is:
[tex]\begin{gathered} y-2=-\frac{1}{3}(x-3)=-\frac{1}{3}x+1\rightarrow \\ y=-\frac{1}{3}x+1+2=-\frac{1}{3}x+3 \end{gathered}[/tex]so the answer is:
[tex]y=-\frac{1}{3}x+3[/tex]