Given:
[tex]y=-(x-3)^2+2[/tex]
Let's graph the function and list the transformation.
Apply the vertex form of a parabola:
[tex]y=a(x-h)^2+k[/tex]
Thus, we have:
a = -1
h = 3
k = 2
Given that a is negative, the parabola opens down.
Vertex of the parabola is: (h, k) ==> (
