Area of the triangle, XYZ = 1/2(XZ)(AY)
Therefore,
[tex]XZ=\sqrt[]{(0+2)^2+(2-6)^2_{}}[/tex][tex]\begin{gathered} XZ=\sqrt[]{4+16} \\ =\sqrt[]{20} \\ =4.47 \end{gathered}[/tex]
Similarly,
[tex]AY=\sqrt[]{(3+1)^2+(6-4)^2}[/tex][tex]\begin{gathered} AY=\sqrt[]{16+4} \\ =\sqrt[]{20} \\ =4.47 \end{gathered}[/tex]
Therefore, the area is,
[tex]\begin{gathered} \frac{1}{2}\times XZ\times AY=\frac{1}{2}\times\sqrt{20}\times\sqrt[]{20} \\ =\frac{1}{2}\times20 \\ =10 \end{gathered}[/tex]
So, area of triangle XYZ is 10
