The expression of the linear with the given two points (a,b) & (c,d) is :
[tex]y-b=\frac{d-b}{c-a}(x-a)[/tex]We have given (10,-10) & (-10,0)
such that a =10, b=-10, c=-10, d=0
[tex]\begin{gathered} y-b=\frac{d-b}{c-a}(x-a) \\ y-(-10)=\frac{0-(-10)}{-10-10}(x-10) \\ y+10=\frac{10}{-20}(x-10) \\ y+10=-\frac{1}{2}(x-10) \\ 2y+20=-x+10 \\ x+2y+20-10=0 \\ x+2y+10=0 \end{gathered}[/tex]The required linear equation is x + 2y + 10 = 0
Answer : x + 2y + 10 = 0