Given
The one base of trapezoid is given BC=x.
The other base of trapezoid is given AD=x+2.
The average base is MN=13.
Explanation
To find the bases of the trapezoid,
[tex]\frac{1}{2}(b_1+b_2)=b_{avg}[/tex]
Substitute the values,
[tex]\begin{gathered} \frac{1}{2}(x+x+2)=13 \\ 2x+2=26 \\ 2x=24 \\ x=12 \end{gathered}[/tex]
Then the bases are find by substitute the values of x.
BC=12
AD=12+2=14
Answer
Hence the bases are
BC=12cm and AD=14cm
