Answer :
Given:
Point A has a potential
[tex]V_A\text{ =356.86 V}[/tex]Point B has a potential
[tex]V_B=\text{ 112.27 V}[/tex]The work done is W = 0.91 mJ
To find the charge in micro Coulombs.
Explanation:
The charge can be calculated as
[tex]\begin{gathered} Q=\frac{W}{V_B-V_A} \\ =\frac{0.91\times10^{-3}}{112.27-356.86} \\ =-3.72\times10^{-6}\text{ C} \\ =-3.72\text{ }\mu C \end{gathered}[/tex]The charge is -3.72 micro Coulomb