Answer :
Let length, l=8 mm.
Braedth, b=2 mm.
The perimeter of the rectangle is,
[tex]\begin{gathered} P=2(l+b) \\ P=2(8+2) \\ P=2\times10 \\ P=20mm^2 \end{gathered}[/tex]Therefore, the perimeter of the rectangle is 20 mm^2.
Let length, l=8 mm.
Braedth, b=2 mm.
The perimeter of the rectangle is,
[tex]\begin{gathered} P=2(l+b) \\ P=2(8+2) \\ P=2\times10 \\ P=20mm^2 \end{gathered}[/tex]Therefore, the perimeter of the rectangle is 20 mm^2.