Answer :
The given equation is,
[tex]x^2-3x+2=0[/tex]Using Quadratic Formula,
[tex]\begin{gathered} x=\frac{-(-3)\pm\sqrt[]{(-3)^2-4(1)(2)}}{2} \\ =\frac{3\pm1}{2} \\ =2,1 \end{gathered}[/tex]Thus, 1 and 2 are required solution.
The given equation is,
[tex]x^2-3x+2=0[/tex]Using Quadratic Formula,
[tex]\begin{gathered} x=\frac{-(-3)\pm\sqrt[]{(-3)^2-4(1)(2)}}{2} \\ =\frac{3\pm1}{2} \\ =2,1 \end{gathered}[/tex]Thus, 1 and 2 are required solution.