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Answer :

Given:

The initial speed of the bicycle is,

[tex]u=4\text{ m/s}[/tex]

The final speed of the bicycle is,

[tex]v=15\text{ m/s}[/tex]

The time interval is,

[tex]t=5\text{ s}[/tex]

The acceleration is given as,

[tex]a=\frac{v-u}{t}[/tex]

substituting the values we get,

[tex]\begin{gathered} a=\frac{15-4}{5} \\ =\frac{11}{5} \\ =2.2m/s^2 \end{gathered}[/tex]

Hence the acceleration is 2.2 m/s^2.