Given:
The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.
Combined, an architect and a lawyer earn $ 207 thousand.
Then, let the average yearly of an architect be: x
and let average yearly of a lawyer: 2x - 24000
- The average yearly salary of an architect
We have the expression:
[tex]x+(2x-24000)=207000[/tex]
Then solve for x
[tex]\begin{gathered} x+2x-24000=207000 \\ 3x-24000=207000 \\ 3x-24000+24000=207000+24000 \\ 3x=231000 \\ \frac{3x}{3}=\frac{231000}{3} \\ x=77000 \end{gathered}[/tex]
Answer 1: $77 thousand
- The average yearly salary of a lawyer
Substituting the value of x:
[tex]2x-24000=2(77000)-24000=154000-24000=130000[/tex]
Answer 2: $130 thousand
