Answer :
Answer: The slope of the line perpendicular to a provided slope is in general as follows:
[tex]m_p=-\frac{1}{m}[/tex]Therefore for the particular provided case, it is as follows:
[tex]\begin{gathered} m=\frac{\Delta y}{\Delta x}=\frac{3-2}{0-3}=-\frac{1}{3} \\ \\ m=-\frac{1}{3} \\ \\ \therefore\rightarrow \\ \\ m_p=-\frac{1}{m}=-\frac{1}{(-\frac{1}{3})}=3 \\ \\ m_p=3 \end{gathered}[/tex]Therefore the new slope is 3.