Answer :
The quadratic equation is hx²+x+2hx+h=1.
Simplify the equation.
[tex]hx^2+2hx+h-1=0[/tex]Solve the quadratic equatiion.
[tex]x=\frac{-2h\pm\sqrt[]{4h^2-4h(h-1)}}{2h}[/tex][tex]x=\frac{-2h\pm\sqrt[]{4h^2-4h^2+4h}}{2h}[/tex][tex]x=\frac{-2h\pm\sqrt[]{4h}}{2h}=\frac{-2h\pm2\sqrt[]{h}}{2h}=\frac{-h\pm\sqrt[]{h}}{h}[/tex][tex]x=\frac{-h+\sqrt[]{h}}{h},\frac{-h-\sqrt[]{h}}{h}[/tex]Hence the value of x ae obatained for the quadratic equations.