Answer :
Given:
AB = 4x + 1
AC = 5x + 20
And we have:
[tex]AC=AB+BC[/tex]Substitute the values:
[tex]5x+20=4x+1+BC[/tex]And solve for BC:
[tex]5x+20-4x-1=4x+1+BC-4x-1[/tex]Add like terms:
[tex]x+19=BC[/tex]Answer: BC = x + 19
Given:
AB = 4x + 1
AC = 5x + 20
And we have:
[tex]AC=AB+BC[/tex]Substitute the values:
[tex]5x+20=4x+1+BC[/tex]And solve for BC:
[tex]5x+20-4x-1=4x+1+BC-4x-1[/tex]Add like terms:
[tex]x+19=BC[/tex]Answer: BC = x + 19