Can someone please help me find the value of X?

Given a right angle triangle
We need to find the angle x
As shown:
The opposite side to the angle x = 6
The adjacent side to the angle x = 11
So, we will find x using the tan function as follows:
[tex]\begin{gathered} \tan x=\frac{opposite}{adjacent}=\frac{6}{11} \\ \\ x=\tan ^{-1}\frac{6}{11}\approx28.61 \end{gathered}[/tex]rounding to the nearest tenth
x = 28.6