Answer :
Solution
A standard deck of cards has 4 suits: Hearts, Clubs, Spades, and Diamonds
Each suite contains an ace, 2, 3, 4,5,6,7,8,9,10, jack, queen, and king, a total of 13 cards
Therefore a standard pack of cards has 4 x13 cards = 52 cards/elements
An expression for probability is
[tex]P(A)\text{ = }\frac{No\text{ of required events}}{No\text{ of total possible events}}[/tex]The question requires us to find the probability of picking an Ace or a Club
No of Aces = 4 across all the suits
No of Clubs = 4 across all suits
Total number of cards = 52
[tex]\begin{gathered} \text{Probability of Aces = }\frac{4}{52} \\ \text{Probability of Clubs =}\frac{4}{52} \end{gathered}[/tex]The probability of picking an Ace or a Club is
[tex]\frac{4}{52}+\frac{4}{52}=\frac{8}{52}=\frac{2}{13}[/tex]Answer = 2/13