Given:
We get the points A(-3,2), B(-1,1) and C(-3,-2) from the graph.
The transformation of points down 2 units and right 3 units can be written as follows.
[tex](x,y)\rightarrow(x+3,y-2)[/tex]
The image of A(-3,2) is
[tex]A(-3,2)\rightarrow(-3+3,2-2)[/tex]
[tex]A(-3,2)\rightarrow(0,0)[/tex]
We get the point (0,0).
The image of B(-1,1) is
[tex]B(-1,1)\rightarrow(-1+3,1-2)[/tex]
[tex]B(-1,1)\rightarrow(2,-1)[/tex]
We get the point (2,-1).
The image of C(-3,-2).
[tex]C(-3,-2)\rightarrow(-3+3,-2-2)[/tex]
[tex]C(-3,-2)\rightarrow(0,-4)[/tex]
We get the point (0,-4).
Hence the points of the image is
(0,0), (-3,-2) and (0,-4).
Option C is correct.
