What is the area of the sector of the circle below, if the radius is 11 cm and the central angle < AOB measures 29 °. (round answer to the nearest tenth)

The area of the red sector is given by:
[tex]\pi\cdot r^2\cdot\frac{(\angle AOB)}{360\degree}=\pi\cdot11^2\cdot\frac{29\degree}{360\degree}\approx30.6\text{ cm}^2[/tex]