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Answer :

A)

[tex]\begin{gathered} \angle3(x-8)\text{ and }\angle2(x+10) \\ \text{Are alternate angles, therefore:} \\ \angle3(x-8)=\angle2(x+10) \\ 3(x-8)=2(x+10) \\ 3x-24=2x+20 \\ \text{Solve for x:} \\ x=44 \end{gathered}[/tex]

B)

[tex]\begin{gathered} \angle4x-12\text{ and }\angle120\text{ are supplementary angles, so:} \\ \angle4x-12+\angle120=180 \\ 4x-12+120=180 \\ \text{Solve for x:} \\ 4x=180-120+12 \\ 4x=72 \\ x=\frac{72}{4} \\ x=18 \end{gathered}[/tex]