ANSWER:
-2
STEP-BY-STEP EXPLANATION:
We have the following expression:
[tex]\mleft(\frac{x^2-4}{x^2+4x+4}\mright)\mleft(x^2-x-6\mright)[/tex]
In this case, the only way that the function becomes discontinuous is when the denominator is equal to 0, that is, we must equal the denominator to 0 and in this way we will be able to know the value that x cannot take.
[tex]\begin{gathered} x^2+4x+4=0 \\ x^2+4x+4=(x+2)^2 \\ (x+2)^2=0 \\ x+2=0 \\ x=-2 \end{gathered}[/tex]
Therefore, x cannot have a value of -2, since if it takes this value, the denominator is 0 and the division by 0 is not defined.
