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Answer :

1) The first thing to do in this exercise, is to analyze in which interval from that piecewise function does the point fall.

part 1)

Note that 2 is in [-1,5) so:

[tex]h(2)\Rightarrow h(2)=(2)^2+2\Rightarrow h(2)=6[/tex]

part 2)

-3 is in (-∞,-1), So h(x)=-4x+6:

[tex]h(-3)=-4(-3)+6\Rightarrow h(-3)=12+6\Rightarrow h(-3)=18[/tex]

Part 3)

-1

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