Answer :
[tex]\begin{gathered} P_{abs}=690KPa \\ P_{gauge}=? \\ P_{abs}=P_{atm}+P_{gauge} \\ \text{Solving }P_{gauge} \\ P_{gauge}=P_{abs}-P_{atm} \\ P_{atm}=101.3\text{ Kpa} \\ P_{gauge}=690KPa-101.3\text{ Kpa} \\ P_{gauge}=588.7KPa=588,700Pa \\ \text{The gauge pressure is }588,700Pa \end{gathered}[/tex]