The given coordinates are :
(x,y) = (-4,-3), (-2,-2), (0,-1),(2,0), (4,1)
The general equation of the line is express as :
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Substitute the value and simplify for the y:
[tex]\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ y-(-3)=\frac{-2-(-3)}{-2-(-4)}(x-(-4)) \\ y+3=\frac{-2+3}{-2+4}(x+4) \\ y+3=\frac{1}{2}(x+4) \\ y=\frac{1}{2}x+2-3 \\ y=\frac{1}{2}x-1 \end{gathered}[/tex]
So, the equation is : y = 1/2x - 1
Answer : B) y = 1/2x - 1
