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Answer :

ANSWER

[tex]\frac{1}{12}[/tex]

EXPLANATION

We want to find the probability that a number less than 2 is rolled on the blue cube and an odd number is rolled on the green cube.

On a number cube, there are six numbers and only one number less than 2.

This implies that the probability that a number less than 2 is rolled on the blue cube is:

[tex]P(b)=\frac{1}{6}[/tex]

On a number cube, there are three odd numbers.

This implies that the probability that an odd number is rolled on the green cube is:

[tex](g)=\frac{3}{6}[/tex]

To find the probability that a number less than 2 is rolled on the blue cube and an odd number is rolled on the green cube, find the product of the probabilities above:

[tex]\begin{gathered} P=P(b)*P(g) \\ \\ P=\frac{1}{6}*\frac{3}{6} \\ \\ P=\frac{1}{12} \end{gathered}[/tex]

That is the answer.

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