Answer:
Explanation:
We start by declaring the null hypothesis
The null hypothesis here is that OHS averages 65 tardines per day
Now, let us get the alternative
We start by getting the p-value, which is an extension of the z value
The z value can be calculated as:
[tex]\begin{gathered} z\text{ = }\frac{x-\mu}{\sigma} \\ \\ z\text{ = }\frac{65-59}{4.5}\text{ = 1.333} \end{gathered}[/tex]
Now, we get the value:
[tex]p\text{ = (z < 1.333)}[/tex]
For a two-tailed test, we have that:
[tex]p\text{ = 0}.183518[/tex]
Now, let us get our conclusion
From the value of p, we can see that the result is not significant
Since p is greater than the level of significance, we accept the null hypothesis (The principal's claims) and say there is no convincing evidence that the average number of tardines is different from the principal's claims
