Given data:
Cost of develop: $9300
Cost of factory each toy: $30
n is the number of toys
[tex]C=mn+b[/tex]
m is the cost of factory each toy
b is the cost of develop
A)
[tex]C=30n+9300[/tex]
B) find C when n=1900
[tex]\begin{gathered} C=30(1900)+9300 \\ C=66300 \end{gathered}[/tex]
The total cost to produce n=1900 toys is $66300
C) find n when C=42300
[tex]\begin{gathered} 42300=30n+9300 \\ Subtract\text{ 9300 in both sides of the equation:} \\ 42300-9300=30n+9300-9300 \\ 33000=30n \\ \\ \text{Divide both sides of the equation into 30:} \\ \frac{33000}{300}=\frac{30}{30}n \\ \\ 1100=n \\ \\ \\ \\ \\ n=1100 \end{gathered}[/tex]
With $42300, a total of 1100 toys can
